{"id":18243,"date":"2024-03-03T02:45:09","date_gmt":"2024-03-03T02:45:09","guid":{"rendered":"https:\/\/soicau5055.minhngocxoso.com\/?p=18243"},"modified":"2024-03-03T02:45:09","modified_gmt":"2024-03-03T02:45:09","slug":"soi-cau-mien-bac-chinh-xac-tu-giai-dac-biet-ket-hop-giai-7","status":"publish","type":"post","link":"https:\/\/dudoanlodevip.com\/soi-cau-mien-bac-chinh-xac-tu-giai-dac-biet-ket-hop-giai-7\/","title":{"rendered":"soi c\u1ea7u mi\u1ec1n b\u1eafc ch\u00ednh x\u00e1c t\u1eeb gi\u1ea3i \u0111\u1eb7c bi\u1ec7t k\u1ebft h\u1ee3p gi\u1ea3i 7"},"content":{"rendered":"\n
Soi c\u1ea7u mi\u1ec1n b\u1eafc ch\u00ednh x\u00e1c t\u1eeb gi\u1ea3i \u0111\u1eb7c bi\u1ec7t k\u1ebft h\u1ee3p gi\u1ea3i 7. \u0110\u00e2y l\u00e0 ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 cao c\u1ea5p v\u00e0 kh\u00f4ng m\u1ea5y ai chia s\u1ebb b\u00ed k\u00edp th\u1ef1c s\u1ef1. C\u00e1ch soi c\u1ea7u mi\u1ec1n b\u1eafc ch\u00ednh x\u00e1c ch\u01b0a bao gi\u1edd thua. \u00c1p d\u1ee5ng t\u1eeb gi\u1ea3i \u0111\u1eb7c bi\u1ec7t k\u1ebft h\u1ee3p gi\u1ea3i 7. Mang l\u1ea1i k\u1ebft qu\u1ea3 c\u00f3 t\u1ec9 l\u1ec7 ch\u00ednh x\u00e1c cao.<\/p>\n\n\n\n
Ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 n\u00e0y s\u1ebd \u00e1p d\u1ee5ng t\u1eeb k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc. Ch\u00fang ta s\u1ebd ch\u1ec9 s\u1eed d\u1ee5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e0 gi\u1ea3i 7 \u0111\u1ec3 th\u1ef1c hi\u1ec7n soi c\u1ea7u. Ch\u00fang ta s\u1ebd t\u00ednh \u0111\u01b0\u1ee3c c\u1eb7p l\u00f4 c\u1ee7a c\u00e1c ng\u00e0y sau \u0111\u00f3. Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y \u0111\u00e3 v\u00e0 \u0111ang \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng cho b\u00e0i vi\u1ebft soi c\u1ea7u xsmb mi\u1ec5n ph\u00ed. \u0110\u01b0\u1ee3c chia s\u1ebb tr\u00ean websiteSoi c\u1ea7u mi\u1ec1n b\u1eafc ch\u00ednh x\u00e1c t\u1eeb gi\u1ea3i \u0111\u1eb7c bi\u1ec7t k\u1ebft h\u1ee3p gi\u1ea3i 7<\/p>\n\n\n\n
Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u00fang ta s\u1ebd d\u1ef1a v\u00e0o s\u1ef1 tr\u00f9ng h\u1ee3p c\u1ee7a k\u1ebft qu\u1ea3 ng\u00e0y h\u00f4m tr\u01b0\u1edbc v\u00e0 h\u00f4m sau. \u0110\u1ec3 \u00e1p d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p hi\u1ec7u qu\u1ea3, c\u00e1c b\u1ea1n c\u1ea7n ph\u1ea3i \u0111\u00e1nh 2 con l\u00f4 trong 3 ng\u00e0y. Khi n\u00e0o tr\u00fang m\u1edbi chuy\u1ec3n sang \u0111\u00e1nh con kh\u00e1c, kh\u00f4ng \u0111\u01b0\u1ee3c b\u1ecf gi\u1eefa ch\u1eebng.<\/p>\n\n\n\n
S\u1ed1 v\u1ed1n \u0111\u1ec3 theo ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u mi\u1ec1n b\u1eafc ch\u00ednh x\u00e1c t\u1eeb gi\u1ea3i \u0111\u1eb7c bi\u1ec7t k\u1ebft h\u1ee3p gi\u1ea3i 7 kh\u00f4ng qu\u00e1 l\u1edbn. H\u1ea7u h\u1ebft ai c\u0169ng c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng \u0111\u01b0\u1ee3c. Ch\u00fang ta s\u1ebd \u0111i t\u1eebng b\u01b0\u1edbc \u0111\u1ec3 th\u1ef1c hi\u1ec7n theo ph\u01b0\u01a1ng ph\u00e1p n\u00e0y.<\/p>\n\n\n\n
Ch\u00fang ta s\u1ebd l\u1ea5y t\u1ed5ng s\u1ed1 \u0111\u1ea7u v\u00e0 s\u1ed1 cu\u1ed1i gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a ng\u00e0y h\u00f4m nay. N\u1ebfu nh\u01b0 t\u1ed5ng l\u1edbn h\u01a1n 10 th\u00ec ta c\u1ed9ng ti\u1ebfp t\u1eebng s\u1ed1 c\u1ee7a t\u1ed5ng \u0111\u00f3. N\u1ebfu t\u1ed5ng b\u1eb1ng 10 th\u00ec la l\u1ea5y b\u1eb1ng 0. N\u1ebfu nh\u01b0 t\u1ed5ng nh\u1ecf h\u01a1n 10 th\u00ec ta l\u1ea5y lu\u00f4n t\u1ed5ng \u0111\u00f3.<\/p>\n\n\n\n
V\u00ed d\u1ee5 1<\/strong>: Gi\u1ea3i \u0111\u1eb7c bi\u1ec7t x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc l\u00e0: 35516 \u2013 Ta c\u00f3 3 l\u00e0 s\u1ed1 \u0111\u1ea7u v\u00e0 6 l\u00e0 s\u1ed1 cu\u1ed1i.<\/p>\n\n\n\n Nh\u01b0 v\u1eady t\u1ed5ng s\u1ebd = 9. V\u1eady t\u1ed5ng nh\u1ecf h\u01a1n 10 ta s\u1ebd l\u1ea5y lu\u00f4n t\u1ed5ng \u0111\u00f3 l\u00e0 9<\/strong>.<\/p>\n\n\n\n V\u00ed d\u1ee5 2:<\/strong> N\u1ebfu nh\u01b0 ta c\u00f3 k\u1ebft qu\u1ea3 xsmb l\u00e0: 95512, ta c\u00f3 t\u1ed5ng = 11 (l\u1edbn h\u01a1n 10). Ta s\u1ebd ti\u1ebfp t\u1ee5c l\u1ea5y 1 + 1 = 2. V\u1eady k\u1ebft qu\u1ea3 ta c\u00f3 t\u1ed5ng 12.<\/strong><\/p>\n\n\n\n T\u1eeb k\u1ebft qu\u1ea3 \u1edf b\u01b0\u1edbc 1 ch\u00fang ta s\u1ebd l\u1ea5y b\u00f3ng c\u1ee7a t\u1ed5ng \u0111\u00f3. Ta s\u1ebd \u0111\u01b0\u1ee3c m\u1ed9t s\u1ed1 v\u00e0 g\u1ecdi t\u1ea1m l\u00e0 X.<\/p>\n\n\n\n V\u00ed d\u1ee5:<\/strong> Nh\u01b0 t\u1ed5ng b\u00ean tr\u00ea ch\u00fang ta c\u00f3 s\u1ed1 9. V\u1eady b\u00f3ng c\u1ee7a 9 s\u1ebd l\u00e0 4. V\u00e0 ch\u00fang ta c\u00f3 X = 4<\/strong><\/p>\n\n\n\n K\u1ebft qu\u1ea3 xsmb s\u1ebd c\u00f3 4 gi\u1ea3i 7. M\u1ed7i gi\u1ea3i bao g\u1ed3m 2 con s\u1ed1. T\u1ea5t c\u1ea3 ch\u00fang ta s\u1ebd c\u00f3 8 s\u1ed1 trong gi\u1ea3i 7 n\u00e0y.<\/p>\n\n\n\n Ta s\u1ebd l\u1ef1a ch\u1ecdn 2 s\u1ed1 xu\u1ea5t hi\u1ec7n nhi\u1ec1u nh\u1ea5t trong 8 s\u1ed1 \u0111\u00f3. N\u1ebfu nh\u01b0 nhi\u1ec1u s\u1ed1 xu\u1ea5t hi\u1ec7n b\u1eb1ng nhau ta s\u1ebd \u01b0u ti\u00ean s\u1ed1 xu\u1ea5t hi\u1ec7n tr\u01b0\u1edbc t\u00ednh t\u1eeb tr\u00e1i qua ph\u1ea3i theo k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1. Cu\u1ed1i c\u00f9ng ta \u0111\u01b0\u1ee3c 2 s\u1ed1 v\u00e0 g\u1ecdi ch\u00fang l\u00e0 A v\u00e0 B.<\/p>\n\n\n\n V\u00ed d\u1ee5: Ch\u00fang ta c\u00f3 gi\u1ea3i 7 l\u00e0 83, 43, 86, 29<\/strong>. Ta th\u1ea5y s\u1ed1 3 xu\u1ea5t hi\u1ec7n 2 l\u1ea7n, s\u1ed1 8 c\u0169ng xu\u1ea5t hi\u1ec7n 2 l\u1ea7n.<\/p>\n\n\n\n Nh\u01b0 v\u1eady ch\u00fang ta s\u1ebd c\u00f3 s\u1ed1 8 v\u00e0 s\u1ed1 3. V\u1eady A = 8<\/strong> v\u00e0 B = 3<\/strong><\/p>\n\n\n\nB\u01b0\u1edbc 2: Soi c\u1ea7u mi\u1ec1n b\u1eafc ch\u00ednh x\u00e1c t\u1eeb b\u00f3ng l\u00f4 \u0111\u1ec1.<\/h3>\n\n\n\n
B\u01b0\u1edbc 3: Soi c\u1ea7u mi\u1ec1n b\u1eafc ch\u00ednh x\u00e1c t\u1eeb gi\u1ea3i 7<\/h3>\n\n\n\n